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1.`P^(1//2)`2.`P`3.`P^(1//4)`4.`P^(2)`

Answer :

ASolution :

According the Freundlich adsorption isotherm <br> `x/m=kp^(1//n) :. "log" x/m=logk+1/n log p` <br> According to the graph slope `=2/4=1/2 :. n=2:.x/m prop p^(1//2)`